Liquid Mixing Calculator

Calculate the final concentration, volume, or amount needed when mixing two liquids.

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Instructions

1

Enter data
Enter content, paste text or load a file from disk.
2

Click the button
The tool will immediately process your data in the browser.
3

Get the result
Copy the finished text or save the file to your device.

                                                function runTool() {

                                                  return "Result ready in 0.1s";

                                                }

Liquid 1 (e.g. cold water)

Time (m₁)

Initial temperature (T₁)

°C

Specific heat capacity (c₁)

J/(kg·K)

Liquid 2 (e.g. hot water)

Time (m₂)

Initial temperature (T₂)

°C

Specific heat capacity (c₂)

J/(kg·K)

Decimal places

Complete the form and click the button to see the result.

Specific heat of selected substances

Substance	Specific heat [J/(kg·K)]
Water (liquid)	4186
Ethyl alcohol	2440
Glycerine	2430
Vegetable oil	2000
Ice (at 0°C)	2100
Air (dry)	1005

How does it work? (Heat balance)

The calculation is based on the **heat balance equation** in an isolated system (where there is no heat exchange with the surroundings). The heat absorbed by the colder liquid must be equal to the heat given up by the warmer liquid.

Formula:
Tf = (m₁·c₁·T₁ + m₂·c₂·T₂) / (m₁·c₁ + m₂·c₂)
gdzie:
• m₁, m₂ – masses of individual substances,
• c₁, c₂ – their specific heats,
• T₁, T₂ – their initial temperatures.

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Liquid mixing calculator – final temperature without losses

This calculates toolfinal temperature of the mixturetwo liquids based on massesm1, m2, initial temperaturesT1, T2and specific heatc1, c2. Weight units are supportedm_unit= kg or g, you can set the accuracy with the parameterprecision. Material presets are available in the interface: water, oil, ethanol. The result is presented asThfin °C.

thermodynamics specific heat mixing solutions chemical engineering

Launch the calculator

Formulas and mixing theory

Assumption of thermal equilibrium

We assume no heat loss to the environment and no phase changes. The heat given off by the warmer liquid is equal to the heat absorbed by the cooler liquid.

m1 · c1 · (T1 − Tf) = m2 · c2 · (Tf − T2)

Final temperature formula

Tf = (m1 c1 T1 + m2 c2 T2) / (m1 c1 + m2 c2)

If the specific heats are identical (c1 = c2), the formula simplifies to a weighted average of temperatures with weights equal to masses.

Energy balance

Qdownloaded = m1 · c1 · (T1 − Tf)Qdownloaded = m2 · c2 · (Tf − T2)
Qdelivered = Qdownloaded

Model limitations

No heat loss to the walls and surroundings.
No chemical mixing effects or heat of dissolution.
Specific heatsc1 i c2treated as constant in the considered temperature range.
No evaporation or condensation during mixing.

Form fields and tool logic

m1, m2– liquid mass.m_unit: kg or g. The calculator converts to SI.
T1, T2– initial temperatures of both portions [°C].
c1, c2– specific heat [J/(kg·K)]. Presets: water, oil, ethanol.
precision– number of decimal places in the presentationThf.
Thf– resulting mixture temperature [°C].

After filling in the fields, the calculator verifies the data and displays the result in the sectionResultsas a formatted value with unit.

Units and conversions

Size	Symbol	Units	Default
Mass	m	kg, g	kg
Temperature	T	°C	°C
Specific heat	c	J/(kg·K)	J/(kg·K)
Final temperature	Thf	°C	°C

Reference values of specific heat

Liquid	c [J/(kg·K)]	Comments
Water (20°C)	4186	Preset water
Mineral oil	~2000	Preset oil, fraction dependent
Ethanol	~2440	Ethanol preset
Salts of aqueous solutions	3400–4100	Concentration dependent
Ethylene glycol 50%	~3300	Refrigeration mixture

Step-by-step calculation examples

Example 1 - water with water

m1 = 1.5 kg, T1 = 80°C, c1 = 4186
m2 = 0.5 kg, T2 = 20°C, c2 = 4186

Tf = (1.5·4186·80 + 0.5·4186·20) / (1.5·4186 + 0.5·4186) = (502,320 + 41,860) / 8,372 ≈ 65.1°C. The result shows a strong influence of the larger mass of the hot portion.

Example 2 - water and oil

m1 = 1.0 kg, T1 = 60°C, c1 = 4186
m2 = 1.0 kg, T2 = 20°C, c2 = 2000

Tf = (1·4186·60 + 1·2000·20) / (1·4186 + 1·2000) = (251,160 + 40,000) / 6,186 ≈ 47.1°C. The lower C of the oil reduces its ability to absorb heat, so Tf is closer to the water temperature.

Example 3 - ethanol with water

m1 = 0.8 kg, T1 = 10°C, c1 = 2440 (ethanol)
m2 = 0.8 kg, T2 = 40°C, c2 = 4186 (water)

Tf = (0.8·2440·10 + 0.8·4186·40) / (0.8·2440 + 0.8·4186) = (19,520 + 134 0... ) / 5,181 ≈ 30.8°C. Differences in c can be seen in the shift of the final temperature towards water.

Example 4 - other mass units

m_unit = g
m1 = 250 g, T1 = 90°C, c1 = 4186
m2 = 750 g, T2 = 25°C, c2 = 4186

The calculator converts g to kg. Tf = (0.25·4186·90 + 0.75·4186·25) / (0.25·4186 + 0.75·4186) ≈ 40.0°C.

Common errors and pitfalls

Incompatible mass units. Changem_unitif the data is in grams.
Incorrect specific heats. Make sure thatc1 i c2are given in J/(kg·K).
Phase transitions. If one component freezes or boils, the componentsm·Lfor the heat of fusion or vaporization must be added to the balance.
Losses to the environment. The actual Tf is sometimes lower than the model one. Use a correction factor or insulate the vessel.
Strong chemical reactions and heat of dissolution. For exothermic or endothermic concentrations and reactions, the result may differ from the formula.

Practical applications

Quickly estimate mixture temperature in the laboratory and production.
Selection of the proportions of technical fluids and coolants.
Temperature control in food and pharmaceutical processes.
Initial energy balance in exchangers and mixed tanks.
Temperature safety planning for sensitive materials.

Mixing Scenario Table

Scenario	Input	Assumptions	Output
Water to water	m1, T1, m2, T2, c=4186	No losses	Tf
Water with oil	m1, T1, m2, T2, c1=4186, c2≈2000	No reaction	Tf
Water with ethanol	m1, T1, m2, T2, c1≈2440, c2=4186	No pairing	Tf
Multiple units	m_unit=g	Automatic conversion	Tf

How to use the calculator

Enterm1, T1, c1andm2, T2, c2.
Setm_unitto kg or g. If in doubt, leave kg.
Use material presets to quickly completec.
Selectprecisionto the expected readability of the result.
Click calculate and readTfin the results panel.

FAQ

Can I mix fluids with different specific heats?

Yes. The general formula includes variousc1 i c2. The different c makes Tf closer to the temperature of the component with the larger productm·c.

What about the evaporation of ethanol or water?

The model does not take it into account. In conditions of open vessels and high temperatures, losses will occur and Tf will be lower than the calculations.

Does the calculator take into account the temperature of the vessel?

No. If the vessel is cold or hot, make an energy correction or reduce the impact by insulating and preheating.

How to adjust the accuracy of the result?

Setprecisionaccording to the measurement uncertainty. Usually 2 to 3 decimal places is sufficient.

Can I use volume instead of mass?

Yes, but you have to convert the volume to mass by density. Then use m in kg and c in J/(kg·K).

Summary

The liquid mixing calculator quickly and reliably estimates the final temperature of two batches of liquid. It uses a clear energy balance and allows working with various specific heats and mass units. In engineering conditions, correction for losses and possible process effects is recommended. As a tool for preliminary analyzes and teaching, it provides repeatable results and saves time when planning temperature procedures.