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Friction Loss Calculator

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Friction loss calculator in pipelines – Darcy–Weisbach, Colebrook–White, Hazen–Williams

Calculate the pressure drop in pipelines for water, glycol and other liquids: using theDarcy–Weisbach method(with linear and local friction), as well as empiricallyHazen–Williams. The tool calculates theReynolds number, friction coefficient f(including the Colebrook–White equation), takes into account therelative roughness k/D, of the fitting by the K coefficientsorequivalent lengths, and gives the result asΔp[Pa/kPa/bar] andhead drop hf[m] – together withrequired pump head.

Darcy–Weisbach Colebrook–White Hazen–Williams Reynolds Re roughness k local losses K equivalent length pressure drop Δp head H

Run the friction loss calculator Formulas, tables and examples

Calculation range

  • Linear friction:Δplinand hfby the Darcy–Weisbach method for internal diameter, flow and viscosity.
  • Local friction:elbows, valves, tees – throughKorequivalent length Leq.
  • Reynolds and regimes:laminar, transient, turbulent; model selection forf.
  • Colebrook–White / Swamee–Jain:calculation offfrom k/D without iteration or iteratively.
  • Hazen–Williams:quick estimates for cold water (parameterC).
  • Units and conversions:m, mm, L/s, m³/h, GPM; Pa, kPa, bar; m H2O.
  • Pump:head H = (Δptotal/ ρg) + reserves.

Key formulas

Re = ρ v D / μ
v = 4Q / (π D²)

Q – flow, v – average velocity, D – internal diameter, ρ – density, μ – dynamic viscosity.

hf,lin= f · (L/D) · v² / (2g)
hf,have= ΣK · v² / (2g)
Δp = ρ g (hf,lin+ hf,have)

f – Darcy friction coefficient, K – local coefficients (fittings, fittings), L – length.

Friction coefficient f

Laminar (Re < 2300)

f = 64 / Re

In this range, the result depends only on viscosity and flow – roughness does not matter

Turbulent (Re >~ 4000)

1/√f = −2 log₁₀[(k/D)/3.7 + 2.51/(Re √f)]

Colebrook–White equation – usually solved iteratively. Non-iterative approximation: Swamee–Jain.

f ≈ 0.25 / [log₁₀((k/D)/3.7 + 5.74/Re⁰·⁹)]²

Hazen–Williams (for water, estimation)

hf= 10.67 · L · Q1.852/ (C1.852· D4.87)

D [m], Q [m³/s], L [m];C– coefficient (e.g. 140 for smooth pipes). Method for water at ~5–25°C.

Roughness and typical k values

Pipe material k – roughness [mm] Comments
PE/PVC smooth 0.001–0.01 Low resistance, large C
Copper 0.001–0.015 Very smooth
New steel 0.03–0.1 k increases over time
Galvanized steel 0.1–0.2 Older installations – higher k
Cast iron 0.2–0.5 Municipal pipelines
Concrete 0.3–3.0 Large diameters, channels

Local losses - K coefficients and equivalent lengths

Model K

Each element (elbow, valve, tee) has a coefficientK. The sumΣKcounts the local hf= ΣK·v²/(2g).

Example:2 × 90° elbow (K≈0.9), poppet valve (K≈10) ⇒ ΣK ≈ 11.8.

Equivalent length Leq

Replaces the element with a pipe segment: Leq= (K·D)/f. The sum of L + ΣLeqgives the effective length for linear friction.

Hint: Leqdepends onf, so it is calculated iteratively with friction.

Calculation examples

Example A – water, D=50 mm, L=80 m

Q = 8 m³/h = 0.00222 m³/s. D = 0.05 m ⇒ v = 4Q/(πD²) ≈ 1.13 m/s.

Assume k = 0.05 mm ⇒ k/D = 0.001. Re at 20°C (ρ≈998, μ≈1e−3): Re ≈ 56,500 ⇒ turbulent flow.

Swamee–Jain ⇒ f ≈ 0.020. hf,lin= f·(L/D)·v²/(2g) ≈ 0.020·(80/0.05)·1.13²/(2·9.81) ≈ 2.08 m.

Fittings: 2 × elbow K=0.9; 1 × ball valve K=0.05 ⇒ ΣK = 1.85 ⇒ hf,have≈ 1.85·1.13²/(2·9.81) ≈ 0.12 m.

Total: hf≈ 2.20 m ⇒ Δp ≈ 998·9.81·2.20 ≈ 21.5 kPa ≈ 0.215 bar.

Example B – Hazen–Williams, C=140

The same L and D, Q=8 m³/h. For SI: hf= 10.67·L·Q¹·⁸⁵²/(C¹·⁸⁵²·D⁴·⁸⁷).

Approximate result ~2.1–2.3 m (close to Darcy–Weisbach). Differences depend on C and the scope of applicability.

Example C – influence of diameter

Q = 8 m³/h; change D from 50 mm to 65 mm: v decreases, hfdecreases non-linearly (approx. 40–60%). Larger diameter – lower losses, higher cost.

Example D – glycol 30%

Higher viscosity ⇒ lower Re ⇒ higherfand higher hf. In refrigeration and HVAC, it often determines the selection of the pump.

Required pump lifting height

H = hf+ hstat+ reserves (e.g. 10–20%)

hstat– level difference between suction and discharge. Reserves take into account dirt, installation aging and tolerances.

Units and conversions

Quantity Units Conversions
Flow Q m³/h, m³/s, L/s, L/min, GPM 1 m³/h = 0.2778 L/s = 16.667 L/min
Pressure Δp Pa, kPa, bar 1 bar = 100 kPa = 10⁵ Pa
Height h m H₂O Δp [Pa] = ρ g h ⇒ for water ~ 9.81 kPa/m
Diameter D mm, m mm → m: divide by 1000
Viscosity μ Pa s 1 mPa s = 0.001 Pa s

FAQ

When to use Hazen–Williams?

For quick estimates for water at typical temperatures in smooth pipes. For accurate calculations and other liquids – Darcy–Weisbach.

How to select roughness k?

Select from material tables; for aging installations, adopt a larger k or add a reserve.

Does K for fittings depend on diameter?

Yes, K values ​​are usually published for the Re range and geometry; for large changes in diameter, use the manufacturer's data or Leq.

Re laminar result - what about f?

For Re < 2300 use f = 64/Re. Do not use Colebrook - it does not apply to laminar flow.

How to account for a cascade of episodes?

Sum hfof all segments and elements: linear + local. Finally, convert to Δp and H for the pump.

Design checklist

Inputs

  1. Q or v, Dint, L, material (k), temperature (μ, ρ).
  2. Armature: K or L listeq.
  3. Assumptions for H: hstat, reserves.

Results

  1. Re, f, v.
  2. hf,lin, hf,have, Δp.
  3. H pumps and conversions (kPa, bar, m).

Summary:The Darcy–Weisbach method with the correct selection off(Colebrook–White or Swamee–Jain), taking into account roughness and local losses K, gives reliable results for most process liquids and water. Hazen–Williams is useful for quick estimates. Ultimately, based on the total pressure drop and level difference, you will easily determine the required pump head.

Calculate pressure drop Calculate H for the pump

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